## 35.2 Linear equations: A review

An *example* of a
regression equation is

\[
\hat{y} = -4 + 2x.
\]
Here,
\(x\) refers to the explanatory variable,
\(y\) refers to the *observed* response variable,
and
\(\hat{y}\) refers to the *predicted* values of the response variable.

In general, the equation of a straight line is written as

\[
\hat{y} = {b_0} + {b_1} x
\]
where
\(b_0\) and \(b_1\) are just numbers.
Again,
\(\hat{y}\) refers to the *predicted* (not observed) values of \(y\).

**Example 35.1 (Regression equations)**In the regression equation \(\hat{y} = 15 - 102x\), we have \(b_0=15\) and \(b_1 = -102\).

**Think 35.1 (Regression coefficients)**Consider the regression equation \(\hat{y} = -0.0047x + 2.1\). What are the values of \(b_0\) and \(b_1\)? (Look carefully!)

*order*that’s important.

The numbers \(b_0\) and \(b_1\) are called
*regression coefficients*,
where

- \(b_0\) is a number called the
**intercept**. It is the*predicted*value of \(y\) when \(x=0\). - \(b_1\) is a number called the
**slope**. It is, on average, how much the value of \(y\) changes when the value of \(x\) increases by 1.

We will use software to find the values of \(b_0\) and \(b_1\).
However,
we can roughly guess the values of the *intercept*
by first drawing what looks like a sensible straight line through the data,
and determining what that line predicts for the value of \(y\) when \(x=0\).

A rough guess of the *slope* can be made using the formula

\[
\text{slope}
= \frac{\text{Change in $y$}}{\text{Corresponding change in $x$}}
= \frac{\text{rise}}{\text{run}}.
\]
That is,
a guess of the slope is the *change* in the value of \(y\) (the ‘rise’)
divided by the corresponding *change* in the value of \(x\) (the ‘run’).

To demonstrate, consider the scatterplot in Fig. 35.1. I have drawn a sensible line on the graph to capture the relationship (your line may look a bit different). When \(x = 0\), the regression line predicts the value of \(y\) is about to be 2, so \(b_0\) is approximately 2.

To guess the slope,
use the ‘rise over run’
idea. The animation below may help explain the *rise-over-run* idea.
When the value of \(x\) increases from 1 to 5
(a change of \(5-1=4\)),
the corresponding values of \(y\) change from 5 to 17
(a change of \(17 - 5 = 12\)).
Then,
use the formula:

\[\begin{align*} \frac{\text{rise}}{\text{run}} &= \frac{17 - 5}{5 - 1}\\ &= \frac{12}{4} = 3. \end{align*}\] The value of \(b_1\) is about \(3\). The regression line is approximately \(\hat{y} = 2 + (3\times x)\), usually written as

\[ \hat{y} = 2+3x. \]

The *intercept* has the same measurement units as the response variable.
For example,
with the red-deer data the intercept is measured in ‘grams,’
the measurement units of the molar weight.

*slope*is the ‘measurement units of the response variable,’ per ‘measurement units of the explanatory variable.’ For example, with the red-deer data the slope has the units of ‘grams per year.’

**Example 35.2 (Estimating regression parameters) **A study
(Dunn and Smyth 2018)
examined the number of cyclones \(y\) in the Australian region each year from 1969 to 2005,
and the relationship with a climatological index called the
*Ocean Nino Index* (ONI, \(x\));
see
(Fig. 35.2),

When the value of \(x\) is zero,
the predicted value of \(y\) is about 12;
\(b_0\) is about 12.
(You may get something slightly different.)
Notice that the intercept is the predicted value of \(y\) when \(x=0\),
which is *not* at the left of the graph.

To guess the value of \(b_1\),
use the ‘rise over run’ idea.
When \(x\) is about \(-2\), the predicted value of \(y\) is about 17.
When \(x\) is about \(2\), the predicted value of \(y\) is about 8.
So when the value of \(x\) changes by \(2 - (-2) = 4\),
the value of \(y\) changes by \(8 - 17 = -9\)
(a *decrease* of about 9).
Hence,
the value of \(b_1\) is approximately \(-9/4 = -2.25\).
(You may get something slightly different.)
Notice that the relationship has a *negative* direction,
so the slope must be negative.

Using these guesses of \(b_0 = 12\) and \(b_1 = -2.25\), the regression line is approximately \[ \hat{y} = 12 - 2.25x. \]

In this section,
we have seen how to understand a linear regression equation,
and how an equation can be used to describe a fitted line.
The above method gives a very crude guess
of the values of the intercept \(b_0\) and the slope \(b_1\).
In practice,
*many* reasonable lines could be drawn through a scatterplot of data.
However,
one of those lines is the ‘best fitting line’ in some
sense^{17}.
Software calculates this ‘line of best fit’ for us.

### References

For those who want to know: The ‘line of best fit’ is the line such that the sum of the

*squared*vertical distances between the observations and the line is as small as possible.↩︎