27.7 t0=t+3 GEVP

here we solve the GEVP \[ C(t)v(t,t_0)= \lambda(t,t_0)C(t_0) v(t,t_0) \] for \(t_0=t+3\). the corresponding eigenvalue in the case \(T\to \infty\) \[ \lambda_n(t,t_0)= e^{-E_n(t-t_0)}= e^{-3 E_n} \]

27.7.1 ../../g0.1/out/G2t_T64_L28_msq0-4.900000_msq1-4.650000_l02.500000_l12.500000_mu5.000000_g0.100000_rep0_output

E1_0_px(L28T64) = 0.253146(37) \(\chi^2/dof=\) 47.944

E1_1_px(L28T64) = 0.488244(76) \(\chi^2/dof=\) 1068.3

phi03_p1_meff(L28T64) = 0.37872(13) \(\chi^2/dof=\) 19368

E3_0_p1_vev(L28T64) = 0.5110(14) 0.00010748(38) 0.00320(47) 0.00348(96) 0.3(0.3)e-4 \(\chi^2/dof=\) 0.011414