Laplace smearing
We introduce a fictitious smearing time τ and we solve
∂τϕ(τ,t,→x)=∇2ϕ(τ,t,→x)withϕ(0,t,→x)=ϕ(t,→x).
this smearing do not effect the zero momentum component because the laplacian ∇2=∂2x1+∂2x2+∂2x3 in momentum space is zero
∂τ˜ϕ(τ,t,→p)=|→p|2˜ϕ(τ,t,→p)