27.19 fit QC3 pole g=0.1

minimizing the $\chi^2$ $$\chi^2 =\sum_i \frac{(E_3^{predicted} -E_3^{measured} )}{\sigma^2}$$ the predicted energy is the solution of the three particles quantization condition in the isotropic approximation $$F_3^{iso}(E,\vec P,L)=-1/K^{iso}_3(E^*)\,$$ $F_3$ depend on the result of the two particle phase shift $\delta$ computed before and we parametrise $K_3^{iso}$ as

$$K_3^{iso}= \frac{P[0]}{E_{cm}^2-P[1]}$$ where $P[1]$ represent the mass of the resonance $P[1]=M_R^2$

$$\begin{gather} \chi^2/d.o.f.=0.575448 \\ P[0]=-22533.5\pm (1.3e+03) \\ P[1]=80.5154\pm (0.71) \\ \end{gather}$$ { $$\begin{gather} C=\begin{pmatrix} 1.77e+06& 0.85\\ 0.85& 0.507\\ \end{pmatrix} \end{gather}$$ }