# 25 More about CIs

So far, you have learnt to ask a RQ, design a study, classify and summarise the data, and have also been introduced to confidence intervals.
**In this chapter**, you will learn more about forming *confidence intervals*.
You will learn to

- communicate confidence intervals.
- interpret confidence intervals.

## 25.1 General comments

The previous chapters discussed forming confidence intervals (CI) for estimating a population proportion, and for estimating a mean. CIs in other contexts will also be studied. This chapter discusses some principles that apply to CIs in general.

CIs are formed for an unknown *population* parameter (such as the population proportion \(p\)), using the best estimate of the parameter: the *sample* statistic (such as the sample proportion \(\hat{p}\)).
Most CIs have the form
\[
\text{statistic} \pm (\text{multiplier} \times \text{standard error}),
\]
where \((\text{multiplier} \times \text{standard error})\) is called the *margin of error*.
For an *approximate* \(95\)% CI, the *multiplier* is \(2\) (from the \(68\)--\(95\)--\(99.7\) rule), provided the statistical validity conditions are met.
The statistical validity conditions should always be checked to see if the CI is (at least approximately) statistically valid.

*Confidence intervals* tell us about the unknown *population parameter*, based on what we learn from one the countless possible sample statistics.

## 25.2 About writing conclusions

When reporting a CI, include:

- the CI (including units of measurement, if relevant);
- the level of confidence for the CI (typically, a \(95\)% CI); and
- the value of the statistic (the parameter estimate) and the sample size.

If the CI is an *approximate* CI (e.g., based on using an approximate multiplier of \(2\) from the \(68\)--\(95\)--\(99.7\) rule), this should also be clear.

**Example 25.1 (Writing conclusions) **In Sect. 24.5, the mean cadmium level of peanuts was estimated.
The conclusion given was:

The sample mean cadmium concentration of peanuts is \(\bar{x} = 0.0768\) ppm (s.e.: \(0.00270\); \(n = 290\)), with an approximate \(95\)% CI from \(0.0714\) to \(0.0822\) ppm.

Each of the three elements above are given:

- the CI: \(0.0714\) to \(0.0822\) ppm;
- the level of confidence for the CI: \(95\)%; and
- sample summary information: \(\bar{x} = 0.0768\) ppm; s.e.: \(0.00270\); \(n = 290\).

In addition, the CI is flagged as a *approximate* \(95\)% CI.

## 25.3 About interpreting CIs

Interpreting CIs correctly takes care.
The *correct* interpretation (Def. 23.3) of a \(95\)% CI is:

The CI is an interval which contains the unknown parameter \(95\)% of the time (over repeated sampling).

That is, if we *repeated* the process (of selecting a sample of \(290\) peanuts and compute the CI for each sample) numerous time, \(95\)% of those confidence intervals formed would contain the value of the parameter.
This is the idea shown in
the animation in Sect. 23.4.

In practice, this definition is unsatisfying, since we only ever have *one* sample, not many samples.
Furthermore, since the value of the parameter is unknown (after all, the reason for taking a sample was to *estimate* the value of the parameter), we don't know if the CI from *our* single sample includes the population parameter or not.

Two reasonable alternative interpretations for a \(95\)% CI are:

- The \(95\)% CI gives a range of values of the unknown parameter that could reasonably (with \(95\)% confidence) have produced our observed value of the statistic.
- There is a \(95\)% chance that our \(95\)% CI straddles the value of the parameter.

These alternatives are adequate and common interpretations.

Frequently, the CI is described as having a \(95\)% chance of containing the population parameter.
This is not strictly correct (the CI either *does* or *does not* contains the value of the population parameter), but is a common and a brief paraphrase for the correct interpretation above.

I use this analogy:
most people say the sun rises in the east.
This is incorrect; the sun doesn't *rise* at all.
People *say* the sun rises in the east as a convenient way to explain that the earth rotates on its axis, and we see the sun each morning in the east.
Similarly, most people interpret a CI as an interval with a certain chance of containing the value of the population parameter, even though it is technically incorrect.

**Example 25.2 (Interpreting CIs) **In Example 25.1, the approximate \(95\)% CI was from \(0.0714\) to \(0.0822\).
The correct interpretation is:

If many samples of \(290\) peanuts were taken, and the approximate \(95\)% CI computed for each one, about \(95\)% of those CIs would contain the population mean.

Our CI may or may not include the value of \(\mu\), however. We might say:

This \(95\)% CI (from \(0.0714\) to \(0.0822\) ppm) has a \(95\)% chance of straddling the actual value of \(\mu\).

or

The range of values of \(\mu\) that could plausibly (with \(95\)% confidence) have produced \(\bar{x} = 0.0768\) is between \(0.0714\) to \(0.0822\) ppm.

In practice, the CI is usually interpreted as:

There is a \(95\)% chance that the population mean level of cadmium in peanuts is between \(0.0714\) to \(0.0822\) ppm.

This last statement is not strictly correct, but is commonly-used, and sufficient for our use.

## 25.4 About statistical validity

When constructing confidence intervals, *statistical validity conditions* must be true to ensure the mathematics behind the calculations are sound.
For instance, if the sampling distribution has an approximate normal distribution, the statistical validity conditions ensure that the approximation is sufficiently accurate for the \(68\)--\(95\)--\(99.7\) rule to apply.
If these conditions are *not* met, the sampling distribution may not be close to an approximate normal distribution, so the \(68\)--\(95\)--\(99.7\) rule (on which the CI is based) may not be appropriate, and the CI itself may be inappropriate.
Of course, if the statistical validity conditions are close to be satisfied, then the resulting confidence interval will still be reasonably useful.

Besides checking the statistical validity condition, the *internal validity* and *external validity* of the study should be discussed (Fig. 25.1).
In addition, CIs also require that the sample size is less than about \(10\)% of the population size; this is almost always the case.

## 25.5 Quick revision exercises

Are the following statements *true* or *false*?

- True or false: CIs
*always*have \(95\)% confidence. - True or false: Statistical validity concern
*generalisability*of the results.

- True or false: CIs always include the value of the
*population*parameter.

- True or false: All other things being equal, a \(95\)% CI is
*wider*than a \(90\)% CI.

- The 'multiplier times the standard error' is called the
*margin of error*. - We are fairly sure (but
*not certain*) that the CI includes the value of the statistic.

## 25.6 Exercises

Answers to odd-numbered exercises are available in App. E.

**Exercise 25.1 **Hirst and Stedman (1962) computed a \(95\)% CI to estimate the proportion of trees with apple scab, and found \(\hat{p} = 0.314\) and \(\text{s.e.}(\hat{p}) = 0.091\).
What would be wrong with the following conclusion?

An approximate \(95\)% CI for the sample proportion is between \(0.223\) and \(0.405\).

**Exercise 25.2 **Hirst and Stedman (1962) computed a \(95\)% CI to estimate the proportion of trees with apple scab, and found \(\hat{p} = 0.314\) and \(\text{s.e.}(\hat{p}) = 0.091\).
What would be wrong with the following conclusion?

This CI means we are \(95\)% confident that between \(22.3\) and \(40.5\) trees are infected with apple scab.

**Exercise 25.3 **A study of sodium intake in Thailand found the \(95\)% CI for the mean daily sodium intake for subjects with a secondary school education was \(3565\) to \(3903\) mg.
What would be wrong with the following conclusion?

This CI means that approximately \(95\)% of the subjects had a daily sodium intake between \(3565\) to \(3903\) mg.

**Exercise 25.4 **A study of sodium intake in Thailand found the \(95\)% CI for the mean daily sodium intake for subjects with a secondary school education was \(3565\) to \(3903\) mg.
What would be wrong with the following conclusion?

A \(95\)% CI for the sample mean daily sodium intake is between \(3565\) to \(3903\) mg.