11 Day 10
Announcements
You may have noticed I’ve been behind on grading corrections/getting lectures posted early…
I also have coursework, and for those who understand this image hopefully it’ll help convey why I’m less timely:
Exam 1 is October 2nd
We do not have the official room assignments yet, please do not ask me
- You will know when I know
There will be a full exam review prior
Exam test prep materials will be posted to the bookdown
- I might consider giving solutions
Homework 4 Corrections are posted
If you want anything graded in the next 3 weeks submit it within the next 10 days
- Otherwise, know in your heart of hearts that I am ignoring your emails
Review
Why do we study probability in statistics?
Probability
- A number between 0 and 1 that tells us how likely a given “event” is to occur
Probability equal to 0 means the event cannot occur
- P(x)=0
Probability equal to 1 means the event must occur
- P(x)=1
Probability equal to 1/2 means the event is as likely to occur as it is to not occur
- P(x)=0.5
Probability close to 0 (but not equal to 0) means the event is very unlikely to occur
- The event may still occur, but we’d tend to be surprised if it did
Probability close to 1 (but not equal to 1) means the event is very likely to occur
- The event may not occur, but we’d tend to be surprised if it didn’t
Experiment (in context of probability):
- An activity that results in a definite outcome where the observed outcome is determined by chance
Sample space:
- The set of ALL possible outcomes of an experiment; denoted by S
- Flip a coin once
S={H,T}
- Randomly select a person and then determine blood type
S={A,B,AB,O}
Event
A subset of outcomes belonging to sample space S
A capital letter towards the beginning of the alphabet is used to denote an event
Simple event
- An event containing a single outcome in the sample space S
- Example:
S={HH,HT,TH,TT}
Let A = "we observe two heads" = \{HH\} is a simple event
Compound event
- An event formed by combining two or more events (thereby containing two or more outcomes in the sample space S)
- Example:
S = \{HH, HT, TH, TT\}
Let B = "we observe a head in the first or in the second flip" = \{HT, TH, HH\} is a compound event
Subjective Probability
Probability is assigned based on judgement or experience
i.e. expert opinion, personal experience, “vibe math”
Classical Probability
Make some assumptions in order to build a mathematical model from which we can derive probabilities
It’s not vibe math but it can definitely feel like it
P(A) = \frac{\text{number of outcomes in event } A}{\text{total number of outcomes in } S}.
Relative or Empirical Probability
- Think of the probability of an event as the proportion of times that the event occurs
P(x) \approx \frac{\text{number of times x is observed}}{\text{number of samples}}
Law of Large Numbers
As the size of our sample (i.e., number of experiments) gets larger and larger:
The relative frequency of the event of our interest gets closer and closer to the true probability
Probability Continued
A probability model assigns a probability to each possible event constructed from the simple events in a particular sample space describing a particular experiment
For a finite sample space with n simple events, e.g. S = \{E_1, E_2, \dots, E_n\}:
- The probability model assigns a number p_i to event E_i where P(E_i) = p_i so that:
0 \leq p_i \leq 1
p_1 + p_2 + \dots + p_n = 1 (as a consequence, P(S) = 1)
For an equally-likely probability model, the probability of observing E_i is:
P(E_i) = p_i = \frac{1}{n}
If A is an event in an equally-likely sample space S and contains k outcomes, then:
P(A) = \frac{\text{No. of outcomes in } A}{\text{No. of outcomes in } S} = \frac{k}{n}
Example
- Suppose there are 200 potential blood donors, and their blood types are classified & counted in the table below:
\begin{array}{|c|c|c|c|c|c|} \hline \textbf{Blood Type} & \textbf{A} & \textbf{B} & \textbf{AB} & \textbf{O} & \textbf{Total} \\ \hline \text{Count} & 80 & 20 & 10 & 90 & 200 \\ \hline \end{array}
Our experiment involves selecting one donor and finding out what the blood type is
We make a random selection so that everyone has the same chance of being selected
- What kind of sample is this?
The sample space S is the set of all 200 donors
The probability model for this experiment is given as follows:
\begin{array}{|c|c|c|c|c|c|} \hline \textbf{Outcome} & \textbf{A} & \textbf{B} & \textbf{AB} & \textbf{O} & \textbf{Total} \\ \hline \text{Count} & 0.4 & 0.1 & 0.05 & 0.45 & 1 \\ \hline \end{array}
If A is an event in S, then the event where A does not occur is called the complement of A
Denote the complement of A by A^c – read this as “A-complement”
Complement Rule
P(A^c) = 1 - P(A) \quad \text{or} \quad P(A) = 1 - P(A^c)
Note: This rule is useful when P(A) is difficult to calculate but P(A^c) is easy (or vice versa)
Example
Suppose we roll a fair 6-sided die twice, then S contains 36 equally-likely outcomes in the form of 36 ordered pairs, i.e. (1, 1), (1, 2), \dots, (6, 5), (6, 6)
Let A be “roll doubles”
- Then P(A) = \frac{6}{36} = \frac{1}{6}
A^c is the event we “do not roll doubles”, and:
P(A^c) = 1 - P(A) = 1 - \frac{1}{6} = \frac{5}{6}
Note: We could have counted the number of non-doubles in S, but this requires more effort
Unions and Intersections
From this point forward, there will be picture drawing
The union of two events A and B, denoted A \cup B, are all outcomes that belong to A, B, or both
- Saying A \cup B is equivalent to saying “A or B”
The intersection of two events A and B, denoted A \cap B, are all outcomes that belong to both A and B
- Saying A \cap B is equivalent to saying “A and B”
Example In rolling a die once, consider events A and B:
A: Roll an even number: \{2, 4, 6\}
B: Roll a number greater than 4: \{5, 6\}
\Rightarrow A \text{ or } B = \{2, 4, 5, 6\}
\Rightarrow A \text{ and } B = \{6\}
Example 1
In a statistics class of 30 students, there were 13 men and 17 women. Two of the men and three of the women received an A in this course. A student is chosen at random from the class
Find the probability that the student is a woman
Find the probability that the student received an A
Find the probability that the student is a woman or received an A
Mutual Exclusivity
Two events A and B are mutually exclusive if they do not share any common outcomes
Roll a die:
A: Roll a 1 or a 2: \{1, 2\}
B: Roll an even number: \{2, 4, 6\}
C: Roll a 3, 4, or 5: \{3, 4, 5\}
Events A and C are mutually exclusive. Knowing that we rolled a 1 or 2 implies that we did not roll a 3, 4, or 5
Events A and B are not mutually exclusive as A \text{ and } B = \{2\}
Addition rule for mutually exclusive events A and B:
P(A \text{ or } B) = P(A) + P(B)
Conditional Probability
A conditional probability of an event is a probability obtained with the additional information that some other event has already occurred
P(A|B) denotes the conditional probability of event A given that event B has already occurred
P(A|B) = \frac{P(A \text{ and } B)}{P(B)}
- Similarly,
P(B|A) = \frac{P(A \text{ and } B)}{P(A)}
Example 2
An economist predicts a 60% chance that stock A will perform poorly and a 25% chance that stock B will perform poorly. There is also a 16% chance that both stocks will perform poorly
What is the probability that stock A performs poorly given that stock B performs poorly?
Example 3
Below table shows the results from an experiment in which college students were given either 4 quarters or a $1 bill
\begin{array}{|c|c|c|} \hline \textbf{} & \textbf{Purchased Gum} & \textbf{Kept the Money} \\ \hline \text{Students Given Four Quarters} & 27 & 12 \\ \hline {\text{Students Given a 1 Dollar Bill}} & 19 & 33 \\ \hline \end{array}
Find the probability of randomly selecting a student who:
spent the money, given that the student was given 4 quarters (round to 3 decimal places)
kept the money, given that the student was given a $1 bill (round to 3 decimal places)
Multiplication Rule
From the definition of the conditional probability
P(A|B) = \frac{P(A \text{ and } B)}{P(B)},
we have the following multiplication rule for finding P(A \text{ and } B):
P(A \text{ and } B) = P(A|B) P(B)
Independence
Events A and B are independent if the outcome of A does not affect the outcome of B and vice versa
In terms of conditional probability, the probability of A does not change given B happened and vice versa
That is, A and B are independent if one of the following is true:
P(A|B) = P(A)
P(B|A) = P(B)
P(A \text{ and } B) = P(A)P(B)
(You can show that all three statements are equivalent.)