18.6 QC3 fit 3par

We minimise the $\chi^2$ $$\chi^2= \sum_i \frac{( E_3^{predicted} - E_3^{latt})^2}{\sigma^2}$$ Were $E_3^{predicted}$ is the solution of the three particle quantization condition in the isotropic approximation $$F_{3}^{iso}(E,\vec{P},L)=-1/{ K}_{df}^{iso}(E^*)$$

$$K_{df}^{iso}=\frac{P[0] M_0^2 }{E^2-M_r^2}+ P[2]$$

$$\begin{gather} \chi^2/d.o.f.=1.48818 \\ P[0]=58.2874\pm (5.4) \\ P[1]=9.13589\pm (0.00077) \\ P[2]=-2800.3\pm (1e+03) \\ \end{gather}$$ { $$\begin{gather} C=\begin{pmatrix} 29& -0.566& -0.592\\ -0.566& 5.96e-07& 0.827\\ -0.592& 0.827& 1.02e+06\\ \end{pmatrix} \end{gather}$$ }