15.2 偏微分方程
ReacTran 的几个关键函数介绍
一维热传导方程
{∂y∂t=D∂2y∂x2参数 D=0.01,边界条件 yt,x=0=0,yt,x=1=1,初始条件 yt=0,x=sin(πx)。
library(ReacTran)
<- 100
N <- setup.grid.1D(x.up = 0, x.down = 1, N = N)
xgrid <- xgrid$x.mid
x <- 0.01
D.coeff <- function(t, Y, parms) {
Diffusion <- tran.1D(
tran C = Y, C.up = 0, C.down = 1,
D = D.coeff, dx = xgrid
)list(
dY = tran$dC,
flux.up = tran$flux.up,
flux.down = tran$flux.down
)
}<- sin(pi * x)
yini <- seq(from = 0, to = 5, by = 0.01)
times <- ode.1D(
out y = yini, times = times, func = Diffusion,
parms = NULL, dimens = N
)
image(out,
grid = xgrid$x.mid, xlab = "times",
ylab = "Distance", main = "PDE", add.contour = TRUE
)

图 15.2: 一维热传导方程的数值解热力图
二维拉普拉斯方程
{∂2u∂2x+∂2u∂y2=0边界条件
{ux=0,y=ux=1,y=0∂ux,y=0∂y=0∂ux,y=1∂y=πsinh(π)sin(πx)它有解析解
u(x,y)=sin(πx)cosh(πy)
其中 x∈[0,1],y∈[0,1]
<- function(x, y) {
fn sin(pi * x) * cosh(pi * y)
}<- seq(0, 1, length.out = 101)
x <- seq(0, 1, length.out = 101)
y <- outer(x, y, fn) z
image(z, col = terrain.colors(20))
contour(z, method = "flattest", add = TRUE, lty = 1)

图 15.3: 解析解的二维图像
persp(z,
theta = 30, phi = 20,
r = 50, d = 0.1, expand = 0.5, ltheta = 90, lphi = 180,
shade = 0.1, ticktype = "detailed", nticks = 5, box = TRUE,
col = drapecol(z, col = terrain.colors(20)),
border = "transparent",
xlab = "X", ylab = "Y", zlab = "Z",
main = ""
)

图 15.4: 解析解的三维透视图像
求解 PDE
<- 0.2
dx <- setup.grid.1D(-100, 100, dx.1 = dx)
xgrid <- xgrid$x.mid
x <- xgrid$N
N
<- exp(-0.05 * x^2)
uini <- rep(0, N)
vini <- c(uini, vini)
yini <- seq(from = 0, to = 50, by = 1)
times
<- function(t, y, parms) {
wave <- y[1:N]
u1 <- y[-(1:N)]
u2 <- u2
du1 <- tran.1D(C = u1, C.up = 0, C.down = 0, D = 1, dx = xgrid)$dC
du2 return(list(c(du1, du2)))
}
<- ode.1D(
out func = wave, y = yini, times = times, parms = NULL,
nspec = 2, method = "ode45", dimens = N, names = c("u", "v")
)