2.1 Undestanding terminology
- More complex events can be determined as union, intersection or complement of the simpler events
P(A∪B)=probabillity of occurrence of A or B or at least one of themP(A∩B)=probabillity of occurrence of A and B at the same timeP(¯A)=probabillity of non-occurrence of A
- If A and B are mutually exclusive events, P(A∩B)=0, we can apply addition rule, and if they are independent we can apply multiplication rule:
P(A∪B)=P(A)+P(B)P(A∩B)=P(A)⋅P(B)
Probability P(A∩B) is often called joint probability
If events are not independent the conditional probability makes sense
The conditional probability P(A|B) is the probability that event A will occur given that event B has already occurred
P(A|B)=P(A∩B)P(B)P(B|A)=P(A∩B)P(A)
Example 2.1 The experiment consists of tossing two coins. Let event A=“at least one head occurred”, B=“two tails occurred”, and C=“the same outcome on both coins”. Determine the following:
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P(A)=___________
P(B)=___________
P(C)=___________
Which events are mutually exclusive?
Which events are complementary?
P(A∪B)=___________
P(B∪C)=___________
P(A∩C)=___________
Are events A and C independent?
P(A|C)=___________
P(C|A)=___________
Example 2.2 Let event G=“taking a meth class”. Let event H=“taking a science class”. Then, G∩H=“taking a math class and a science class”. Suppose P(A)=0.6, P(H)=0.5, and P(G∩H)=0.3. Are G and H independent?
Example 2.3 One high school has 200 seniors of whom 140 will be going to college next year. Forty will be going directly to work. The remainder are taking a gap year. Fifty of the seniors going to college play sports. Thirty of the seniors going directly to work play sports. Five of the seniors taking a gap year play sports.
What is the probability that a senior is taking a gap year?
What is the probability that a senior does not play sports?
What is the probability that a senior is taking a gap year if he plays sports?