2.1 Undestanding terminology

  • More complex events can be determined as union, intersection or complement of the simpler events

P(AB)=probabillity of occurrence of A or B or at least one of themP(AB)=probabillity of occurrence of A and B at the same timeP(¯A)=probabillity of non-occurrence of A

  • If A and B are mutually exclusive events, P(AB)=0, we can apply addition rule, and if they are independent we can apply multiplication rule:

P(AB)=P(A)+P(B)P(AB)=P(A)P(B)

  • Probability P(AB) is often called joint probability

  • If events are not independent the conditional probability makes sense

  • The conditional probability P(A|B) is the probability that event A will occur given that event B has already occurred

P(A|B)=P(AB)P(B)P(B|A)=P(AB)P(A)

Example 2.1 The experiment consists of tossing two coins. Let event A=“at least one head occurred”, B=“two tails occurred”, and C=“the same outcome on both coins”. Determine the following:

  1. S={}

  2. P(A)=___________

  3. P(B)=___________

  4. P(C)=___________

  5. Which events are mutually exclusive?

  6. Which events are complementary?

  7. P(AB)=___________

  8. P(BC)=___________

  9. P(AC)=___________

  10. Are events A and C independent?

  11. P(A|C)=___________

  12. P(C|A)=___________

Example 2.2 Let event G=“taking a meth class”. Let event H=“taking a science class”. Then, GH=“taking a math class and a science class”. Suppose P(A)=0.6, P(H)=0.5, and P(GH)=0.3. Are G and H independent?

Example 2.3 One high school has 200 seniors of whom 140 will be going to college next year. Forty will be going directly to work. The remainder are taking a gap year. Fifty of the seniors going to college play sports. Thirty of the seniors going directly to work play sports. Five of the seniors taking a gap year play sports.

  1. What is the probability that a senior is taking a gap year?

  2. What is the probability that a senior does not play sports?

  3. What is the probability that a senior is taking a gap year if he plays sports?