6 đ Limit Theorems

Figure 6.1: âAreUnormalâ by Enrico Chavez
6.1 Markovâs and Chebyshevâs Inequalities
We will start by overviewing two inequalities that allow the computation of upper bounds for probability statements and play an important role in stablishing the convergence results weâll see further in this chapter.
6.2 Sequences of Random Variables
We would like to say something about how these random variables behave as n gets larger and larger (i.e. as n tends towards infinity, denoted by nââ )
The study of such limiting behaviour is commonly called a study of `asymptoticsâ â after the word asymptote used in standard calculus.
6.2.1 Example: Bernoulli Trials and their sum
Let ËZ denote a dichotomous random variable with ËZâźB(p). A sequence of Bernoulli trials provides us with a sequence of values ËZ1,ËZ2,...,ËZn,... %where each ËZi is such that
\begin{eqnarray*} \Pr("Success")=\Pr \left( \tilde{Z}_{i}=1\right) = p & \text{and} & \Pr("Failure")=\Pr \left( \tilde Z_{i}=0\right) = 1-p \end{eqnarray*}
Now let S_n=\sum_{s=1}^n \tilde Z_s, the number of âSuccessesâ in the first n Bernoulli trials. This yields a new sequence of random variables
\begin{eqnarray*} S_{1} &=& \tilde Z_{1} \\ S_{2} &=&\left( \tilde Z_{1}+ \tilde Z_{2}\right)\\ &&\vdots \\ S_{n} &=&\left( \tilde Z_{1}+ \tilde Z_{2}+\cdots + \tilde Z_{n}\right) = \sum_{i=1}^n \tilde Z_i \end{eqnarray*}
This new sequence is such that S_n\sim B(n,p) for each n.
Now consider the sequence:
{P}_n=S_n/n,
for n=1,2,\ldots, corresponds to the proportion of `Successesâin the first n Bernoulli trials.
It is natural to ask how the behaviour of {P}_n is related to the true probability of a `Successâ (p).
Specifically, the open question at this point is: \
âDo these results imply that {P}_n collapses onto the true p as n increases, and if so, in what way?â \
To gain a clue, let us consider the simulated values of {P}_n.
6.3 Convergence in Probability (\overset{p}{\rightarrow })
More formally,
6.3.1 Operational Rules for \overset{p}{\rightarrow }
Let us itemize some rules. To this end, let a be any (nonrandom) number so:
If X_{n}\overset{p}{\rightarrow } \alpha then
aX_{n}\overset{p}{\rightarrow }a\alpha and
a+X_{n}\overset{p}{\rightarrow }a+\alpha,
-
If X_{n}\overset{p}{\rightarrow }X then
- aX_{n}\overset{p}{\rightarrow }aX and
- a+X_{n}\overset{p}{\rightarrow }a+X
-
If X_{n}\overset{p}{\rightarrow }\alpha and Y_{n}\overset{p}{\rightarrow }\gamma then
- X_{n}Y_{n}\overset{p}{\rightarrow }\alpha \gamma and
- X_{n}+Y_{n}\overset{p}{\rightarrow }\alpha +\gamma.
-
If X_{n}\overset{p}{\rightarrow }X and Y_{n}\overset{p}{\rightarrow }Y then
-
X_{n}Y_{n}\overset{p}{\rightarrow }X Y and
- X_{n}+Y_{n}\overset{p}{\rightarrow }X +Y
-
X_{n}Y_{n}\overset{p}{\rightarrow }X Y and
Let g\left( x\right) be any (non-random) continuous function. If X_{n}\overset{p}{\rightarrow }\alpha then g\left( X_{n}\right) \overset{p}{\rightarrow }g\left( \alpha \right), and if X_{n}\overset{p}{\rightarrow }X then
g\left( X_{n}\right) \overset{p}{\rightarrow }g\left( X \right).
Suppose X_{1},X_{2},...,X_{n},... is a sequence of random variables with common distribution F_X(x) and moments \mu_r=E [X^r]. At any given point along the sequence, X_{1},X_{2},...,X_{n} constitutes a simple random sample of size n. \
For each fixed sample size n, the rth sample moment is (using an obvious notation) \begin{equation*} M_{(r,n)}=\frac{1}{n}\left( X_{1}^r+X_{2}^r+\cdots +X_{n}^r\right)=\frac{1}{n}\sum_{s=1}^nX_s^r\,, \end{equation*} and we know that E[M_{(r,n)}]=\mu_r\quad\text{and}\quad Var(M_{(r,n)})=\frac{1}{n}(\mu_{2r}-\mu_r^2)\,.
Now consider the sequence of sample moments M_{(r,1)},M_{(r,2)},...,M_{(r,n)},... or, equivalently, \{M_{(r,i)}\}_{i=1}^{n}.
6.3.2 Convergence of Sample Moments as a motivationâŚ
The distribution of M_{(r,n)} (which is unknown because F_X(x) has not been specified) is thus concentrated around \mu_r for all n, with a variance which tends to zero as n increases. \
So the distribution of M_{(r,n)} becomes more and more concentrated around \mu_r as $n $ increases and therefore we might that \begin{equation*} M_{(r,n)}\overset{p}{\rightarrow }\mu_r. \end{equation*}
In fact, this result follows from what is known as the Weak Law of Large Numbers (WLLN).
6.3.4 The WLLN and Chebyshevâs Inequality
- First note that E[\overline{Y}_n]=\mu_Y and Var(\overline{Y}_n)=\sigma_Y^2/n.
- Now, according to Chebyshevâs inequality \begin{eqnarray*} \Pr \left( |\overline{Y}_{n}-\mu_Y| <\varepsilon\right) &\geq &1-\frac{E\left[ \left( \overline{Y}_{n}-\mu_Y \right) ^{2}\right] }{\varepsilon^{2}} \\ &=&1-\frac{\sigma_Y ^{2}/n}{\varepsilon^{2}} \\ &=&1-\frac{\sigma_Y ^{2}}{n\varepsilon^{2}}\geq 1-\delta \end{eqnarray*} for all n>\sigma_Y^2/(\varepsilon^2\delta).
- Thus the WLLN is proven, provided we can verify Chebyshevâs inequality.
- Note that by considering the limit as n\rightarrow \infty we also have% \begin{equation*} \lim_{n\rightarrow \infty }\Pr \left( \left\vert \overline{Y}_{n}-\mu_Y\right\vert <\varepsilon\right) \geq \lim_{n\rightarrow \infty }\left( 1-\frac{\sigma^{2}}{n\varepsilon^{2}}\right) =1\,, \end{equation*} again implying that \left( \overline{Y}_{n}-\mu_Y \right) \overset{p}{\rightarrow }0.
If p\lim_{n\rightarrow\infty}(X_n-X)=0 then X_{n}\overset{D}{\rightarrow }X.
Let a be any real number. If X_{n}\overset{D}{\rightarrow }X, then aX_{n}\overset{D}{\rightarrow }aX
If Y_{n}\overset{p}{\rightarrow }\phi and X_{n}\overset{D}{% \rightarrow }X, then
Y_{n}X_{n}\overset{D}{\rightarrow }\phi X, and
Y_{n}+X_{n}\overset{D}{\rightarrow }\phi +X
If X_{n}\overset{D}{\rightarrow }X and g\left( x\right) is any continuous function, then g\left( X_{n}\right) \overset{D}{\rightarrow }% g\left( X\right)
The following theorem is often said to be one of the most important results. Its significance lies in the fact that it allows accurate probability calculations to be made without knowledge of the underlying distributions!
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